Ex 8.4, 1 (iii) - Multiply the binomials (2.5š‘™ – 0.5š‘š) and (2.5š‘™ + - Ex 8.4

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Ex 8.4, 1 Multiply the binomials. (iii) (2.5š‘™ – 0.5š‘š) and (2.5š‘™ + 0.5š‘š) (2.5š‘™ – 0.5š‘š)(2.5š‘™ + 0.5š‘š) = 2.5š‘™(2.5š‘™+0.5š‘š)āˆ’0.5š‘š(2.5š‘™+0.5š‘š) = (2.5š‘™ Ɨ 2.5š‘™)+(2.5š‘™ Ɨ 0.5š‘š)āˆ’(0.5š‘š Ɨ 2.5š‘™)āˆ’(0.5š‘š Ɨ 0.5š‘š) = (šŸšŸ“š’/šŸšŸŽĆ—šŸšŸ“š’/šŸšŸŽ)+(šŸšŸ“š’/šŸšŸŽĆ—šŸ“š’Ž/šŸšŸŽ)āˆ’(šŸ“š’Ž/šŸšŸŽĆ—šŸšŸ“š’/šŸšŸŽ)āˆ’(šŸ“š’Ž/šŸšŸŽĆ—šŸ“š’Žš’/šŸšŸŽ) = 625/100Ɨ(š‘™ Ɨ š‘™)+125/100 (š‘™ Ɨ š‘š)āˆ’(125/100)Ɨ(š‘š Ɨ š‘™)āˆ’(25/100)Ɨ(š‘š Ɨ š‘š) = 6.25š‘™^2+1.25š‘™š‘šāˆ’1.25š‘™š‘šāˆ’0.25š‘š^2 = šŸ”.šŸšŸ“š’^šŸāˆ’šŸŽ.šŸšŸ“š’Ž^šŸ

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