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Last updated at Dec. 24, 2018 by Teachoo
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Ex 9.4, 1 Multiply the binomials. (v) (2๐๐ + 3๐^2 ) and (3๐๐ โ 2๐^2 ) (2๐๐ + 3๐^2 )(3๐๐ โ 2๐^2 ) = 2๐๐(3๐๐โ2๐^2 )+3๐^2 (3๐๐โ2๐^2 ) = (2๐๐ร3๐๐)โ(2๐๐ร2๐^2 )+(3๐^2ร3๐๐)โ(3๐^2ร2๐^2 ) = 6๐^2 ๐^2โ4๐๐^3+9๐๐^3โ6๐^4 = ๐๐^๐ ๐^๐+๐๐๐^๐โ๐๐^๐
Ex 9.4
Ex 9.4, 1 (ii)
Ex 9.4, 1 (iii) Important
Ex 9.4, 1 (iv) Important
Ex 9.4, 1 (v) Important You are here
Ex 9.4, 1 (vi) Important
Ex 9.4, 2 (i)
Ex 9.4, 2 (ii)
Ex 9.4, 2 (iii)
Ex 9.4, 2 (iv)
Ex 9.4, 3 (i)
Ex 9.4, 3 (ii)
Ex 9.4, 3 (iii)
Ex 9.4, 3 (iv) Important
Ex 9.4, 3 (v) Important
Ex 9.4, 3 (vi)
Ex 9.4, 3 (vii) Important
Ex 9.4, 3 (viii)
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