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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.3, 3 Find the product. (i) (๐‘Ž^2 ) ร— (2๐‘Ž^22 ) ร— (4๐‘Ž^26 ) (๐‘Ž^2 ) ร— (2๐‘Ž^22 ) ร— (4๐‘Ž^26 ) = ๐‘Ž^2ร—2ร—๐‘Ž^22ร—4ร—๐‘Ž^26 = (2ร—4)ร—(๐‘Ž^2ร—๐‘Ž^22ร—๐‘Ž^26 ) = (2ร—4)ร—(๐‘Ž^(2 + 22 + 26) ) ( ๐‘ฅ^๐‘Ž ร—๐‘ฅ^๐‘ร—๐‘ฅ^๐‘ = ๐‘ฅ^(๐‘Ž + ๐‘ + ๐‘)) = 8ร—๐‘Ž^50 = ๐Ÿ–๐’‚^๐Ÿ“๐ŸŽ Ex 9.3, 3 Find the product. (ii) (2/3 ๐‘ฅ๐‘ฆ)ร—((โˆ’9)/10 ๐‘ฅ^2 ๐‘ฆ^2 ) (2/3 ๐‘ฅ๐‘ฆ)ร—((โˆ’9)/10 ๐‘ฅ^2 ๐‘ฆ^2 ) = 2/3ร—๐‘ฅร—๐‘ฆร—(โˆ’9)/10ร—๐‘ฅ^2ร—๐‘ฆ^2 = (2/3ร—(โˆ’9)/10)ร—(๐‘ฅร—๐‘ฅ^2 )ร—(๐‘ฆร—๐‘ฆ^2 ) = (2/10ร—(โˆ’9)/3)ร—๐‘ฅ^3ร—๐‘ฆ^3 = (1/5ร—โˆ’3)ร—๐‘ฅ^3ร—๐‘ฆ^3 = (โˆ’๐Ÿ‘)/๐Ÿ“ ๐’™^๐Ÿ‘ ๐’š^๐Ÿ‘ Ex 9.3, 3 Find the product. (iii) ((โˆ’10)/3 ๐‘๐‘ž^3 )ร—(6/5 ๐‘^3 ๐‘ž) ((โˆ’10)/3 ๐‘๐‘ž^3 )ร—(6/5 ๐‘^3 ๐‘ž) = (โˆ’10)/3ร—๐‘ร—๐‘ž^3ร—6/5ร—๐‘^3ร—๐‘ž = ((โˆ’10)/3ร—6/5)ร—(๐‘ร—๐‘^3 )ร—(๐‘ž^3ร—๐‘ž) = ((โˆ’10)/5ร—6/3)ร—๐‘^4ร—๐‘ž^4 = (โˆ’2ร—2)ร—๐‘^4ร—๐‘ž^4 = โˆ’๐Ÿ’๐’‘^๐Ÿ’ ๐’’^๐Ÿ’ Ex 9.3, 3 Find the product. (iv) ๐‘ฅร—๐‘ฅ^2ร—๐‘ฅ^3ร—๐‘ฅ^4 ๐‘ฅร—๐‘ฅ^2ร—๐‘ฅ^3ร—๐‘ฅ^4 = ๐‘ฅ^(1 + 2 + 3 + 4) = ๐’™^๐Ÿ๐ŸŽ (๐‘ฅ^๐‘Ž ร—๐‘ฅ^๐‘ = ๐‘ฅ^(๐‘Ž + ๐‘))

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.