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Ex 9.3, 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

Ex 9.3, 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 4
Ex 9.3, 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 5

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Ex 9.3, 4 (b) (b) Simplify a (a2 + a + 1) + 5 and find its value for (i) a = 0, (ii) a = 1 (iii) a = – 1. π‘Ž (π‘Ž^2+π‘Ž+1)+5 = (π‘ŽΓ—π‘Ž^2 )+(π‘ŽΓ—π‘Ž)+(π‘ŽΓ—1)+5 = π‘Ž^3+π‘Ž^2+π‘Ž+5 (i) For 𝒂=𝟎 Putting π‘Ž=0 in expression π‘Ž^3+π‘Ž^2+π‘Ž+5 = (0)^3+(0)^2+0+5 = 0+0+0+5 = πŸ“ (i) For 𝒂=𝟏 Putting π‘Ž=1 in expression π‘Ž^3+π‘Ž^2+π‘Ž+5 = γ€–(1)γ€—^3+ (1)^2+1+5 = 1+1+1+5 = πŸ– (iii) For 𝒂=βˆ’πŸ Putting π‘Ž=βˆ’1 in expression π‘Ž^3+π‘Ž^2+π‘Ž+5 = γ€–(βˆ’1)γ€—^3+ (βˆ’1)^2+(βˆ’1)+5 = (βˆ’1)^2Γ—(βˆ’1)+(1)+(βˆ’1)+5 = 1Γ—(βˆ’1)+1βˆ’1+5 = βˆ’1+1βˆ’1+5 = βˆ’2+6 = πŸ’

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