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Ex 12.3
Ex 12.3, 2 Important You are here
Ex 12.3, 3
Ex 12.3, 4
Ex 12.3, 5 Important
Ex 12.3, 6 (i)
Ex 12.3, 6 (ii) Important
Ex 12.3, 6 (iii)
Ex 12.3, 6 (iv) Important
Ex 12.3, 7 (i) Important
Ex 12.3, 7 (ii)
Ex 12.3, 7 (iii) Important
Ex 12.3, 7 (iv)
Ex 12.3, 7 (v) Important
Ex 12.3, 8 (i)
Ex 12.3, 8 (ii) Important
Ex 12.3, 9 Important
Ex 12.3, 10
Last updated at March 23, 2023 by Teachoo
Ex 12.3, 2 If p = – 2, find the value of: (i) 4p + 7 4p + 7 Putting p = −2 = 4 (−2) + 7 = − 8 + 7 = −1 Ex 12.3, 2 If p = – 2, find the value of: (ii) – 3p2 + 4p + 7 – 3p2 + 4p + 7 Putting p = − 2 = −3 (−2)2 + 4 (−2) + 7 = −3 (4)2 − 8 + 7 = −3 × 4 − 8 + 7 = –12 – 1 = −13 Ex 12.3, 2 If p = – 2, find the value of: (iii) – 2p3 – 3p2 + 4p + 7 – 2p3 – 3p2 + 4p + 7 Putting p = −2 = −2 (−2)3 − 3 (−2)2 + 4 (−2) + 7 = −2 (−8) − 3 (4) − 8 + 7= = 16 − 12 − 1 = 4 − 1 = 3