
Get live Maths 1-on-1 Classs - Class 6 to 12
Ex 12.3
Ex 12.3, 2 Important
Ex 12.3, 3
Ex 12.3, 4
Ex 12.3, 5 Important
Ex 12.3, 6 (i)
Ex 12.3, 6 (ii) Important
Ex 12.3, 6 (iii)
Ex 12.3, 6 (iv) Important
Ex 12.3, 7 (i) Important
Ex 12.3, 7 (ii)
Ex 12.3, 7 (iii) Important
Ex 12.3, 7 (iv)
Ex 12.3, 7 (v) Important
Ex 12.3, 8 (i)
Ex 12.3, 8 (ii) Important You are here
Ex 12.3, 9 Important
Ex 12.3, 10
Last updated at March 16, 2023 by Teachoo
Ex 12.3, 8 (ii) If p = – 10, find the value of p2 – 2p – 100 p2 – 2p – 100 Putting p = −10 = (−10)2 − 2 (−10) − 100 = 100 + 20 − 100 = 120 − 100 = 20