Example 5 - Chapter 12 Class 8 Exponents and Powers
Last updated at Dec. 19, 2018 by
Transcript
Example 5 Find m so that γ(β3)γ^(π+1) Γ γ(β3)γ^5 = γ(β3)γ^7 γ(β3)γ^(π+1) Γ γ(β3)γ^5 = γ(β3)γ^7 γ(β3)γ^(π + 1 + 5) = γ(β3)γ^7 γ(β3)γ^(π + 6) = γ(β3)γ^7 Comparing powers m + 6 = 7 m = 7 β 6 m = 1 (Using π^πΓπ^π=π^(π + π))
Examples
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Example 1 (ii) Important
Example 2 (i) Important
Example 2 (ii)
Example 3 Important
Example 4 (i) Important
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Example 4 (iv)
Example 5 Important You are here
Example 6
Example 7 (i) Important
Example 7 (ii)
Example 8 (i) Important
Example 8 (ii)
Example 9 (i) Important
Example 9 (ii) Important
Example 9 (iii)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.
