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Last updated at March 23, 2023 by Teachoo
Example 5 Find m so that γ(β3)γ^(π+1) Γ γ(β3)γ^5 = γ(β3)γ^7 γ(β3)γ^(π+1) Γ γ(β3)γ^5 = γ(β3)γ^7 γ(β3)γ^(π + 1 + 5) = γ(β3)γ^7 γ(β3)γ^(π + 6) = γ(β3)γ^7 Comparing powers m + 6 = 7 m = 7 β 6 m = 1 (Using π^πΓπ^π=π^(π + π))