# Example 9 - Chapter 11 Class 8 Mensuration

Last updated at Dec. 12, 2018 by Teachoo

Last updated at Dec. 12, 2018 by Teachoo

Example 9 A godown is in the form of a cuboid of measures 60 m Γ 40 m Γ 30 m. How many cuboidal boxes can be stored in it if the volume of one box is 0.8 π^3 ? Given, Length of godown = l = 60 m Breadth of godown = b = 40 m & Height of godown = h = 30 m Also, a cuboidal box is to be stored in godown Volume of cuboidal box = 0.8 m3 So, Number of boxes = (ππππ’ππ ππ πππππ€π)/(ππππ’ππ ππ 1 πππ₯) Volume of godown Volume = πΓπΓβ = 60 Γ 40 Γ 30 = 6 Γ 4 Γ 3 Γ 1000 = 72000 m3 Now, Number of boxes = (ππππ’ππ ππ πππππ€π)/(ππππ’ππ ππ 1 πππ₯) = 72000/0.8 = 72000/(8/10) = (72000 Γ 10)/8 = 90,000 β΄ 90,000 cuboidal boxes can be stored in the godown.