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Chapter 11 Class 8 Mensuration
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Ex 11.1, 4 - A flooring tile has the shape of a parallelogram whose

Ex 11.1, 4 - Chapter 11 Class 8 Mensuration - Part 2
Ex 11.1, 4 - Chapter 11 Class 8 Mensuration - Part 3

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Ex 11.1, 4 A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 𝑚^2? (If required you can split the tiles in whatever way you want to fill up the corners). Given, Tile is in shape of parallelogram And, Base = 24 cm Height = 10 cm Now, Number of tiles required = (𝐴𝑟𝑒𝑎 𝑜𝑓 𝑓𝑙𝑜𝑜𝑜𝑟)/(𝐴𝑟𝑒𝑎 𝑜𝑓 𝑜𝑛𝑒 𝑡𝑖𝑙𝑒) Given, Area of floor = 1080 m2 = 1080 × (100)2 cm2 = 1080 × 100 × 100 cm2 = 1080 × 10000 cm2 Now, finding area of tile Area of tile = Area of parallelogram = Base × Height = 24 × 10 = 240 cm2 Now, Number of tiles required = (𝐴𝑟𝑒𝑎 𝑜𝑓 𝑓𝑙𝑜𝑜𝑜𝑟)/(𝐴𝑟𝑒𝑎 𝑜𝑓 𝑜𝑛𝑒 𝑡𝑖𝑙𝑒) = (1080 × 10000 )/240 = (1080 × 1000)/24 = (540 × 1000)/12 = (90 × 1000)/2 = 45 × 1000 = 45000 ∴ 45000 tiles are required to cover the floor.

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.