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  1. Chapter 11 Class 8 Mensuration
  2. Serial order wise

Transcript

Ex 11.1, 4 A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 ๐‘š^2? (If required you can split the tiles in whatever way you want to fill up the corners). Given, Tile is in shape of parallelogram And, Base = 24 cm Height = 10 cm Now, Number of tiles required = (๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘“๐‘™๐‘œ๐‘œ๐‘œ๐‘Ÿ)/(๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘œ๐‘›๐‘’ ๐‘ก๐‘–๐‘™๐‘’) Given, Area of floor = 1080 m2 = 1080 ร— (100)2 cm2 = 1080 ร— 100 ร— 100 cm2 = 1080 ร— 10000 cm2 Now, finding area of tile Area of tile = Area of parallelogram = Base ร— Height = 24 ร— 10 = 240 cm2 Now, Number of tiles required = (๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘“๐‘™๐‘œ๐‘œ๐‘œ๐‘Ÿ)/(๐ด๐‘Ÿ๐‘’๐‘Ž ๐‘œ๐‘“ ๐‘œ๐‘›๐‘’ ๐‘ก๐‘–๐‘™๐‘’) = (1080 ร— 10000 )/240 = (1080 ร— 1000)/24 = (540 ร— 1000)/12 = (90 ร— 1000)/2 = 45 ร— 1000 = 45000 โˆด 45000 tiles are required to cover the floor.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.