Ex 11.4, 1 - A garden is 90 m long and 75 m broad. A path 5 m wide is

Ex 11.4, 1 - Chapter 11 Class 7 Perimeter and Area - Part 2
Ex 11.4, 1 - Chapter 11 Class 7 Perimeter and Area - Part 3
Ex 11.4, 1 - Chapter 11 Class 7 Perimeter and Area - Part 4
Ex 11.4, 1 - Chapter 11 Class 7 Perimeter and Area - Part 5 Ex 11.4, 1 - Chapter 11 Class 7 Perimeter and Area - Part 6


Transcript

Question 1 A garden is 90 m long and 75 m broad. A path 5 m wide is to be built outside and around it. Find the area of the path. Also find the area of the garden in hectare. Here, Area of path = Area of larger rectangle − Area of smaller rectangle Finding length and breadth of both rectangles Smaller rectangle Length of smaller rectangle = 90 m Breadth of smaller rectangle = 75 m Larger Rectangle 5 m wide path runs all around outside smaller rectangle. ∴ Length of larger rectangle = Length of smaller rectangle + 2 × (5) = 90 + 10 = 100 m Breadth of larger rectangle = Breadth of smaller rectangle + 2 × (5) = 75 + 10 = 85 m Larger rectangle Length = l = 100 m Breadth = b = 85 m Area of larger rectangle = l × b = 100 × 85 = 8500 m2 Smaller rectangle Length = l = 90 m Breadth = b = 75 m Area of smaller rectangle = l × b = 90 × 75 = 6750 m2 Now, Area of path = Area of larger rectangle − Area of smaller rectangle = 8700 − 6750 = 1750 m2 ∴ Area of path is 1750 m2 We also need to find Area of garden in hectares Area of garden Length of garden = l = 90 m Breadth of garden = b = 75 m Area of garden = l × b = 90 × 75 = 6750 m2 = 6750 × 1/10,000 hectare = 6750/10,000 hectare 1 hectare = 10,000 m2 10,000 m2 = 1 hectare 1 m2 = 1/10,000 hectare = 675/1000 hectare = 0.675 hectare ∴ Area of garden is 0.675 hectare

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.