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Ex 9.2, 8 - Chapter 9 Class 7 Perimeter and Area
Last updated at August 14, 2026 by Teachoo
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
- Perimeter of a combination of shapes
-
Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Ex 9.2, 8 Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is Rs 15/m2. (Take π = 3.14) Here, Area to be polished = Area of circular table top Diameter = 1.6 m Radius = r = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = (𝟏.𝟔)/𝟐 = 16/(2 × 10) Area of table top = 𝜋r2 = 3.14 × (𝟖/𝟏𝟎)^𝟐 = 314/100 × 8/10 × 8/10 = (𝟑𝟏𝟒 × 𝟔𝟒)/𝟏𝟎𝟎𝟎𝟎 = 20096/10000 = 2.0096 m2 Now, Cost of polishing 1 m2 area = Rs 15 Cost of polishing 2.0096 m2 area = Rs 15 × 2.0096 = Rs 15 × 𝟐𝟎𝟎𝟗𝟔/𝟏𝟎𝟎𝟎𝟎 = Rs 3 × 20096/2000 = Rs 3 × 𝟏𝟎𝟎𝟒𝟖/𝟏𝟎𝟎𝟎 = Rs 30144/1000 = Rs 30.144 = Rs 30.14 (approx.) ∴ It will cost Rs 30.14 (approx.) to polish the table top
