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Ex 9.2, 2 (a) - Chapter 9 Class 7 Perimeter and Area
Last updated at April 16, 2024 by Teachoo
Chapter 9 Class 7 Perimeter and Area
Concept wise
- Basic Definitions
- Square and Rectangle
- Converting Square to Rectangle
- Area of parallelogram
- Area of triangle
- Circumference of circle
- Perimeter of a combination of shapes
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Area of circle
- Area of combination of figures - two circles, circle and square
- Finding Area of rectangle with path outside/inside
- Finding Area of rectangle with cross roads
- Finding Area of rectangle with triangle
Transcript
Ex 9.2, 2 Find the area of the following circles, given that: (a) radius = 14 mm (𝑇𝑎𝑘𝑒 𝜋=22/7) Radius = r = 14 mm Area of circle = 𝜋 r2 = 𝟐𝟐/𝟕 × (14)2 = 22/7 × 14 × 14 = 22 × 2 × 14 = 44 × 14 = 616 mm2 ∴ Required area is 616 mm2
