Let’s take a rectangle We know that

In a rectangle, opposite sides are equal

AB = CD

&  AD = BC

Let

AB = Length of rectangle = l

BC = Breadth of rectangle = b So,

AB = CD = l

BC = AD = b Now,

Perimeter of rectangle = Sum of all sides

= AB + BC + CD + DA

= l + b + l + b

= 2 l + 2b

= 2 ( l + b)

So,

Perimeter of rectangle = 2 ( l + b)

Let’s take some examples

#### Find perimeter of rectangle where length is 15cm & breadth is 9 cm Given,

Length = l = 15 cm

Breadth = b = 9 cm

Perimeter of rectangle = 2 × (Length + Breadth)

= 2 × (15 + 9)

= 2 × 24

= 48 cm

So, perimeter of rectangle is 48 cm

#### Find perimeter of rectangle where length & breadth are 0.5 m & 0.2 m respectively.

Given,

Length = l = 0.5 cm

Breadth = b = 0.2 cm Perimeter of rectangle = 2 × (Length + Breadth)

= 2 × (0.5 + 0.2)

= (2 × 0.7)

= 1.4 m

= 1.4 × 100 cm               (1m = 100 cm)

= 140 cm

1. Chapter 11 Class 7 Perimeter and Area
2. Concept wise
3. Square and Rectangle

Square and Rectangle

About the Author Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.