# Example 11 - Chapter 10 Class 6 Mensuration

Last updated at Nov. 15, 2018 by Teachoo

Last updated at Nov. 15, 2018 by Teachoo

Transcript

Example 11 By counting squares, estimate the area of the figure 10.9 b. We have, 11 full squares, 3 half filled squares, 8 almost full squares and 5 squares with less than half area So, Area = 11(1) + 3 (1/2) + 8(1) + 5(0) = 11 + 3/2 + 8 + 0 = (11 × 2 + 3 + 8 × 2)/2 = (22 + 3 + 16)/2 = 41/2 = 20.5 square units ∴ Total area required is 20.5 square units Note:- This answer does not match the book answer. If we have done any mistake, please comment below

Finding area by counting squares

Finding area by counting squares

Ex 10.2, 1 (a)

Ex 10.2, 1 (d)

Ex 10.2, 1 (b)

Ex 10.2, 1 (h)

Ex 10.2, 1 (i)

Ex 10.2, 1 (e)

Example 10 Important

Ex 10.2, 1 (c)

Ex 10.2, 1 (f)

Ex 10.2, 1 (g) Important

Ex 10.2, 1 (j)

Ex 10.2, 1 (k)

Example 12

Ex 10.2, 1 (n)

Example 11 Important You are here

Ex 10.2, 1 (l) Important

Ex 10.2, 1 (m) Important

Chapter 10 Class 6 Mensuration

Concept wise

- Perimeter
- Perimeter of Rectangle
- Perimeter of Square
- Perimeter of Triangle
- Perimeter of Pentagon and Hexagon
- Area - Definition
- Finding area by counting squares
- Area of Square
- Area of Rectangle
- Area by splitting into rectangles
- Finding Area by Changing units
- Area questions with both rectangles and squares

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.