Example 11 - Chapter 10 Class 6 Mensuration
Last updated at April 16, 2024 by Teachoo
Finding area by counting squares
Finding area by counting squares
Ex 10.2, 1 (a)
Ex 10.2, 1 (d)
Ex 10.2, 1 (b) Important
Ex 10.2, 1 (h)
Ex 10.2, 1 (i)
Ex 10.2, 1 (e) Important
Example 10
Ex 10.2, 1 (c) Important
Ex 10.2, 1 (f)
Ex 10.2, 1 (g) Important
Ex 10.2, 1 (j) Important
Ex 10.2, 1 (k)
Example 12 Important
Ex 10.2, 1 (n) Important
Example 11 Important You are here
Ex 10.2, 1 (l) Important
Ex 10.2, 1 (m)
Chapter 10 Class 6 Mensuration
Concept wise
- Perimeter
- Perimeter of Rectangle
- Perimeter of Square
- Perimeter of Triangle
- Perimeter of Pentagon and Hexagon
- Area - Definition
-
Finding area by counting squares
- Area of Square
- Area of Rectangle
- Area by splitting into rectangles
- Finding Area by Changing units
- Area questions with both rectangles and squares
Transcript
Example 11 By counting squares, estimate the area of the figure 10.9 b. We have, 11 full squares, 3 half filled squares, 8 almost full squares and 5 squares with less than half area So, Area = 11(1) + 3 (1/2) + 8(1) + 5(0) = 11 + 3/2 + 8 + 0 = (11 × 2 + 3 + 8 × 2)/2 = (22 + 3 + 16)/2 = 41/2 = 20.5 square units ∴ Total area required is 20.5 square units Note:- This answer does not match the book answer. If we have done any mistake, please comment below
