# Ex 10.1, 6 - Chapter 10 Class 6 Mensuration

Last updated at Nov. 15, 2018 by Teachoo

Last updated at Nov. 15, 2018 by Teachoo

Transcript

Ex 10.1, 6 Find the perimeter of each of the following shapes : (a) A triangle of sides 3 cm, 4 cm and 5 cm. Perimeter of ∆ABC = Sum of all sides = AB + BC + CA = 4 + 3 + 5 = 12 cm ∴ Required perimeter is 12 cm Ex 10.1, 6 Find the perimeter of each of the following shapes : (b) An equilateral triangle of side 9 cm. Here, AB = BC = AC = a = 9 cm Perimeter of ∆ABC = 3a = 3 (9) = 27 cm ∴ Required perimeter is 27 cm Ex 10.1, 6 Find the perimeter of each of the following shapes : (c) An isosceles triangle with equal sides 8 cm each and third side 6 cm. Here, AB = AC = 8cm BC = 6cm Perimeter of ∆ABC = AB + BC + CA = 8 + 6 + 8 = 22 cm ∴ Required perimeter is 22 cm

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.