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Ex 10.1, 2 - Chapter 10 Class 6 Mensuration
Last updated at March 16, 2023 by Teachoo
Ex 10.1
Ex 10.1, 1 (a)
Ex 10.1, 1 (b)
Ex 10.1, 1 (c) Important
Ex 10.1, 1 (d)
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Ex 10.1, 1 (f) Important
Ex 10.1, 2 You are here
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Ex 10.1, 6 (a)
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Ex 10.1, 6 (c)
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Ex 10.1, 11 (a)
Ex 10.1, 11 (b)
Ex 10.1, 11 (c) Important
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Transcript
Ex 10.1, 2 The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required? Length = l = 40 cm Breadth = b = 10 cm Length of tape required = Perimeter of rectangle = 2 × (Length + Breadth) = 2 × (40 + 10) = 2 × (50) = 100 cm = 1 m (1m = 100 cm) ∴ 1m of tape is required for sealing rectangular box
