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Ex 11.1, 7 Suppose 2 kg of sugar contains 9 × 10^6 crystals. How many sugar crystals are there in (i) 5 kg of sugar?Given, 2 kg of sugar contains 9 × 10^6 crystals Let 5 kg of sugar contains y crystals. Thus, our table looks like As quantity of sugar increases, the number of crystals also increases. ∴ Quantity of Sugar and Number of Crystals are in direct proportion. 𝟐/(𝟗 × 〖𝟏𝟎〗^𝟔 ) = 𝟓/𝒚 𝑦 × 2 = 5 × 9 × 106 𝑦 × 2 = 45 × 106 𝒚 = 𝟒𝟓/𝟐 × 106 𝑦 = 22.5 × 106 𝑦 = 2.25 × 101 × 106 𝑦 = 2.25 × 101+6 𝒚 = 2.25 × 107 ∴ 5kg of sugar contains 2.25 × 107 crystals Ex 11.1, 7 Suppose 2 kg of sugar contains 9 × 10^6 crystals. How many sugar crystals are there in (ii) 1.2 kg of sugar?Given, 2 kg of sugar contains 9 × 10^6 crystals Let 1.2 kg of sugar contains y crystals. Thus, our table looks like Since Quantity of Sugar and Number of Crystals are in direct proportion. 𝟐/(𝟗 × 〖𝟏𝟎〗^𝟔 ) = (𝟏.𝟐)/𝒚 𝑦 × 2 = 1.2 × 9 × 106 𝑦 × 2 = 12/10 × 9 × 106 𝒚 = 𝟏/𝟐 × 𝟏𝟐/𝟏𝟎 × 9 × 106 𝑦 = 6/10 × 9 × 106 𝑦 = 54/10 × 106 𝒚 = 5.4 × 106 ∴ 1.2 kg of sugar contains 5.4 × 106 crystals

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo