# Example 5 - Chapter 4 Class 8 Practical Geometry

Last updated at Oct. 3, 2018 by Teachoo

Last updated at Oct. 3, 2018 by Teachoo

Example 5 Draw a square of side 4.5 cm. Let’s draw a rough figure In square, All sides are equal ∴ AB = BC = CD = AD = 4.5 cm And, All angles are 90° ∴ ∠ A = ∠ B = ∠ C = ∠ D = 90° So, we draw the square using 3 sides, and 2 angles method Steps of construction 1. Draw side AB of length 4.5 cm 2. Now, we draw 90° from point A Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Now, we draw 90° from point B Taking 4.5 cm as radius, and A as center. Draw an arc. Mark the point where arc and line intersect as D Taking 4.5 cm as radius, and B as center. Draw an arc. Mark the point where arc and line intersect as C Taking 4.5 cm as radius, and A as center. Draw an arc. Mark the point where arc and line intersect as D 5. Taking 4.5 cm as radius, and B as center. Draw an arc. Mark the point where arc and line intersect as C 5. Join CD Label the sides ∴ ABCD is the required square