Check sibling questions
Chapter 4 Class 8 Practical Geometry
Serial order wise

Example 1 - Chapter 4 Class 8 Practical Geometry

Last updated at March 16, 2023 by

Example 1 - Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm

Example 1 - Chapter 4 Class 8 Practical Geometry - Part 2
Example 1 - Chapter 4 Class 8 Practical Geometry - Part 3 Example 1 - Chapter 4 Class 8 Practical Geometry - Part 4 Example 1 - Chapter 4 Class 8 Practical Geometry - Part 5 Example 1 - Chapter 4 Class 8 Practical Geometry - Part 6 Example 1 - Chapter 4 Class 8 Practical Geometry - Part 7

This video is only available for Teachoo black users

Subscribe Now

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for ₹ 499 ₹ 299

Transcript

Example 1 Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm, RS = 5 cm, PS = 5.5 cm and PR = 7 cm. First we draw a rough sketch Let’s construct it Steps of construction 1. Draw diagonal PR of length 7 cm 2. Taking 4 cm as radius, and P as center, draw an arc on top of PR 3. Taking 6 cm as radius, and R as center, draw an arc on top of PR 4. Taking 5.5 cm as radius, and P as center, draw an arc below of PR 5. Taking 5 cm as radius, and R as center, draw an arc below of PR 6. Let Q be the point where arcs intersect on top of PR, and S be the point where arcs intersect below PR Join PQ, PR, PS, SR Label the sides ∴ PQRS is the required quadrilateral

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.