# Ex 14.5, 8 - Chapter 14 Class 6 Practical Geometry

Last updated at Sept. 28, 2018 by Teachoo

Last updated at Sept. 28, 2018 by Teachoo

Transcript

Ex 14.5, 8 Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet? Let’s first draw a circle of radius 3.4 cm We follow these steps 1. Mark point O as center 2. First we make circle of radius 4 cm Since radius is 4 cm, we measure 4 cm using ruler and compass 3. Now keeping compass opened the same length. We keep pointed end at the center, and draw a circle using the pencil end of the compass So, this is the required circle with center O and radius = 4 cm Now, we need to draw two chords. Let two chords be AB & CD We need to draw perpendicular bisectors of AB & CD Drawing perpendicular bisector of AB We follow these steps 1. With A as center, and radius more than half AB, draw an arc on top and bottom of AB With B as center and same radius as before, draw an arc on top and bottom of AB 2. Where the two arcs intersect above AB is point P and where the two arcs intersect below AB is point Q Join PQ Thus, PQ is the perpendicular bisector of AB Now, we draw perpendicular bisector CD Drawing perpendicular bisector of CD We follow these steps 1. With C as center, and radius more than half CD, draw an arc on top and bottom of CD. With D as center and same radius as before, draw an arc on top and bottom of CD 2. Where the two arcs intersect above CD is point R and where the two arcs intersect below CD is point S Join RS Thus, RS is the perpendicular bisector of CD We note that, Perpendicular bisectors of both chords meet at the center of the circle

Chapter 14 Class 6 Practical Geometry

Concept wise

- Basics
- Construction of a circle when its radius is known
- Construction of a line segment of a given length
- Constructing a copy of a given line segment
- Perpendicular to a line through a point on it
- Perpendicular to a line through a point not on it
- Perpendicular bisector of a line segment
- Constructing an angle using protractor
- Bisector of an angle
- Constructing angles using compass
- Constructing a copy of a given angle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.