# Ex 14.5, 2 - Chapter 14 Class 6 Practical Geometry

Last updated at Sept. 28, 2018 by Teachoo

Last updated at Sept. 28, 2018 by Teachoo

Transcript

Ex 14.5, 2 Draw a line segment of length 9.5 cm and construct its perpendicular bisector. Let’s first draw a line segment of length 9.5 cm We follow these steps 1. Draw a line l mark point A on it 2. Since length is 9.5 cm, we measure 9.5 cm using ruler and compass 3. Now keeping compass opened the same length. We keep pointed end at point A, and draw an arc on line l So, the required line segment is (𝐴𝐵) ̅ = 9.5 cm Now, we need to make its perpendicular bisector Let’s follow these steps to make perpendicular bisector of AB 1. Given a line segment AB. 2. Now with A as center, and radius more than half AB, draw an arc on top and bottom of AB 3. Now with B as center, and same radius, draw an arc on top and bottom of AB 4. Where the two arcs intersect above AB is point C and where the two arcs intersect below AB is point D Join CD ∴ CD is the perpendicular bisector of AB

Chapter 14 Class 6 Practical Geometry

Concept wise

- Basics
- Construction of a circle when its radius is known
- Construction of a line segment of a given length
- Constructing a copy of a given line segment
- Perpendicular to a line through a point on it
- Perpendicular to a line through a point not on it
- Perpendicular bisector of a line segment
- Constructing an angle using protractor
- Bisector of an angle
- Constructing angles using compass
- Constructing a copy of a given angle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.