Ex 14.2, 5 - Given AB of length 7.3 cm and CD of length 3.4 cm

Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 2
Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 3 Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 4 Ex 14.2, 5 - Chapter 14 Class 6 Practical Geometry - Part 5

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Transcript

Question 5 Given (𝐴𝐡) Μ… of length 7.3 cm and (𝐢𝐷) Μ… of length 3.4 cm, construct a line segment (π‘‹π‘Œ) Μ… such that the length of (π‘‹π‘Œ) Μ… is equal to the difference between the lengths of (𝐴𝐡) Μ… and (𝐢𝐷) Μ… . Verify by measurement. Given (𝐴𝐡) Μ… = 7.3 cm (𝐢𝐷) Μ… = 3.4 cm We need to make line segment (π‘‹π‘Œ) Μ… such that XY = AB – CD Let’s see how we do it Let’s follow these steps 1. Draw a line l mark point X on it 2. Measure (𝐴𝐡) Μ… = 7.3 cm using compass 3. Now keeping compass opened the same length. We keep pointed end at point X, and draw an arc on line l So, (𝑋𝐡′) Μ… = (𝐴𝐡) Μ… = 7.3 cm. 4. Measure (𝐢𝐷) Μ… = 3.4 cm using compass 5. Now keeping compass opened the same length. We keep pointed end at point B’, and draw an arc on line l So, (π‘Œπ΅β€²) Μ… = (𝐢𝐷) Μ… = 3.4 cm. Thus, required line segment (π‘‹π‘Œ) Μ… = 3.9 cm

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