# Ex 14.2, 4 - Chapter 14 Class 6 Practical Geometry

Last updated at Sept. 28, 2018 by Teachoo

Last updated at Sept. 28, 2018 by Teachoo

Transcript

Ex 14.2, 4 Given (π΄π΅) Μ of length 3.9 cm, construct (ππ) Μ such that the length of (ππ) Μ is twice that of (π΄π΅) Μ . Verify by measurement. (Hint : Construct (ππ) Μ such that length of (ππ) Μ = length of(π΄π΅) Μ ; then cut off (ππ) Μ also has the length of (π΄π΅) Μ .) We are given (π΄π΅) Μ of length 3.9 cm We need to draw (ππ) Μ = 2 Γ (π΄π΅) Μ Letβs follow these steps 1. Draw a line l mark point P on it 2. Measure (π΄π΅) Μ = 3.9 cm using compass 3. Now keeping compass opened the same length. We keep pointed end at point P, and draw an arc on line l So, (ππ) Μ = 3.9 cm. 4. Now keeping compass opened the same length. We keep pointed end at point X, and draw an arc on line l So, (ππ) Μ = 3.9 cm. And (ππ) Μ = 7.8 cm Thus, (ππ) Μ is twice that of (π΄π΅) Μ

Construction of a line segment of a given length

Chapter 14 Class 6 Practical Geometry

Concept wise

- Basics
- Construction of a circle when its radius is known
- Construction of a line segment of a given length
- Constructing a copy of a given line segment
- Perpendicular to a line through a point on it
- Perpendicular to a line through a point not on it
- Perpendicular bisector of a line segment
- Constructing an angle using protractor
- Bisector of an angle
- Constructing angles using compass
- Constructing a copy of a given angle

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.