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  1. Chapter 12 Class 6 Ratio And Proportion
  2. Serial order wise
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Ex 12.2, 4 Determine if the following ratios form a proportion. Also, write the middle terms & extreme terms where the ratios form a proportion. (a) 25 cm : 1 m and Rs 40 : Rs 160 1 m = 100 cm Now, 25 cm : 1 m = (25 ๐‘๐‘š)/(1 ๐‘š) = (25 ๐‘๐‘š)/(100 ๐‘๐‘š) = 25/100 = 1/4 = 1 : 4 Rs 40 : Rs 160 = (๐‘…๐‘  40)/(๐‘…๐‘  60) = 40/160 = 4/16 = 1/4 = 1 : 4 โˆด 25 cm : 1 m = Rs 40 : Rs 160 So, given ratios are in a proportion Here, Middle terms = 1 m, Rs 40 Extreme terms = 25 cm, Rs 160 Ex 12.2, 4 Determine if the following ratios form a proportion. Also, write the middle terms & extreme terms where the ratios form a proportion. (b) 39 litres : 65 litres and 6 bottles : 10 bottles39 litres : 65 litres = (39 ๐‘™๐‘–๐‘ก๐‘Ÿ๐‘’๐‘ )/(65 ๐‘™๐‘–๐‘ก๐‘Ÿ๐‘’๐‘ ) = 39/65 = 3/5 = 3 : 5 6 bottles : 10 bottles = (6 ๐‘๐‘œ๐‘ก๐‘ก๐‘™๐‘’๐‘ )/(10 ๐‘๐‘œ๐‘ก๐‘ก๐‘™๐‘’๐‘ ) = 6/10 = 3/5 = 3 : 5 โˆด 39 litres : 65 litres = 6 bottles : 10 bottles So, Given ratios are in proportion Here, Middle terms = 65 litres, 6 bottles Extreme terms = 39 litres, 10 bottles Ex 12.2, 4 Determine if the following ratios form a proportion. Also, write the middle terms & extreme terms where the ratios form a proportion. (c) 2 kg : 80 kg and 25 g : 625 g2 kg : 80 kg = (2 ๐‘˜๐‘”)/(80 ๐‘˜๐‘”) = 2/80 = 1/40 = 1 : 40 25 g : 625 g = (25 ๐‘”)/(625 ๐‘”) = 25/625 = 5/125 = 1/25 = 1 : 25 โˆด 2 kg : 80 kg โ‰  25 g : 625 g So, given ratio are not in proportion Ex 12.2, 4 Determine if the following ratios form a proportion.Also, write the middle terms & extreme terms where the ratios form a proportion. (d) 200 ml : 2.5 litre and Rs 4 :Rs 50 2.5 litres = 2.5 ร— 1000 ml = 25/10 ร— 1000 ml = 25 ร— 100 ml = 2500 ml 200 ml : 2.5 litre ` = (200 ๐‘š๐‘™)/(2.5 ๐‘™๐‘–๐‘ก๐‘Ÿ๐‘’๐‘ ) = (200 ๐‘š๐‘™)/(2500 ๐‘š๐‘™) = 200/2500 = 2/25 = 2 : 25 Rs 4 : Rs 50 = (๐‘…๐‘  4)/(๐‘…๐‘  50) = 4/50 = 2/25 = 2 : 25 โˆด 200 ml : 2.5 litres = Rs 4 : Rs 50 So, given ratios are in proportion Here, Middle terms = 2.5 litres, Rs 4 Extreme terms = 200 ml, Rs 50

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.