Ex 12.2, 4 - Chapter 12 Class 6 Ratio And Proportion - Part 3

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Ex 12.2, 4 - Chapter 12 Class 6 Ratio And Proportion - Part 4

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  1. Chapter 12 Class 6 Ratio And Proportion
  2. Serial order wise

Transcript

Ex 12.2, 4 Determine if the following ratios form a proportion. Also, write the middle terms & extreme terms where the ratios form a proportion. (b) 39 litres : 65 litres and 6 bottles : 10 bottles39 litres : 65 litres = (39 ๐‘™๐‘–๐‘ก๐‘Ÿ๐‘’๐‘ )/(65 ๐‘™๐‘–๐‘ก๐‘Ÿ๐‘’๐‘ ) = 39/65 = 3/5 = 3 : 5 6 bottles : 10 bottles = (6 ๐‘๐‘œ๐‘ก๐‘ก๐‘™๐‘’๐‘ )/(10 ๐‘๐‘œ๐‘ก๐‘ก๐‘™๐‘’๐‘ ) = 6/10 = 3/5 = 3 : 5 โˆด 39 litres : 65 litres = 6 bottles : 10 bottles So, Given ratios are in proportion Here, Middle terms = 65 litres, 6 bottles Extreme terms = 39 litres, 10 bottles

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.