# Ex 6.5, 2 - Chapter 6 Class 7 Triangle and its Properties

Last updated at Sept. 10, 2018 by Teachoo

Last updated at Sept. 10, 2018 by Teachoo

Transcript

Ex 6.5, 2 ABC is a triangle, right-angled at C. If AB = 25 cm and AC = 7 cm, find BC.In βABC, right angled at C, AB = 24 cm, AC = 7 cm, BC = ? By Pythagoras theorem, γπ΄π΅γ^2 = γπ΄πΆγ^2 + γπ΅πΆγ^2 γ(25)γ^2 = γ(7)γ^2 + γπ΅πΆγ^2 625 = 49 + γπ΅πΆγ^2 625 β 49 = γπ΅πΆγ^2 576 = γπ΅πΆγ^2 γ(24)γ^2 = γπ΅πΆγ^2 Cancelling squares 24 = π΅πΆ π΅πΆ = 24 β΄ π©πͺ = 24 cm Rough 576 = 2 Γ 2 Γ 2 Γ 2 Γ 2 Γ 2 Γ 3 Γ 3 = (2 Γ 2 Γ 2 Γ 3) Γ (2 Γ 2 Γ 2 Γ 3) = 24 Γ 24 = 242

Chapter 6 Class 7 Triangle and its Properties

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.