# Ex 6.5, 1 - Chapter 6 Class 7 Triangle and its Properties

Last updated at Sept. 10, 2018 by Teachoo

Last updated at Sept. 10, 2018 by Teachoo

Transcript

Ex 6.5, 1 PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.In βPQR, right angled at P, PR = 24 cm, PQ = 10 cm, QR = ? By Pythagoras theorem, γππ γ^2 = γππγ^2 + γππ γ^2 γππ γ^2 = γ(10)γ^2 + γ(24)γ^2 γππ γ^2 = 100 + 576 γππ γ^2 = 676 γππ γ^2 = γ(26)γ^2 Cancelling squares ππ = 26 β΄ πΈπΉ = 26 Rough 676 = 2 Γ 2 Γ 13 Γ 13 = (2 Γ 13) Γ (2 Γ 13) = 26 Γ 26 = 262

Chapter 6 Class 7 Triangle and its Properties

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.