Ex 6.5, 3 - A 15 m long ladder reached a window 12 m high from ground

Ex 6.5, 3 - Chapter 6 Class 7 Triangle and its Properties - Part 2

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Transcript

Ex 6.5, 3 A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.Let, PR be the ladder PQ bethe wall Given PR = 15 m PQ = 12 m QR = a = ? Here, ∠Q = 90° as the wall is straight. In Δ PQR By Pythagoras Theorem, 〖𝑃𝑅〗^2 = 〖𝑃𝑄〗^2 + 〖𝑄𝑅〗^2 〖(15)〗^2 = 〖(12)〗^2 + 𝑎^2 225 = 144 + 𝑎^2 225 − 144 = 𝑎^2 81 = 𝑎^2 〖(9)〗^2 = 𝑎^2 Cancelling squares 9 = 𝑎 𝑎 = 9 m ∴ Distance of the foot of the ladder from the wall is 9m.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.