![Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 2](https://d1avenlh0i1xmr.cloudfront.net/d48d09d4-38db-4621-a001-1b8045c8d2ef/slide27.jpg)
![Ex 3.1, 7 - Chapter 3 Class 8 Understanding Quadrilaterals - Part 3](https://d1avenlh0i1xmr.cloudfront.net/f5e0d4ce-954b-4fd7-bca0-ca60fe146f37/slide28.jpg)
Polygons
Last updated at April 16, 2024 by Teachoo
Ex 3.1, 7 (a) Find x + y + zGiven, ∠PAR = x ∠BAC = 90° ∠ABC = 30° ∠ABQ = Z ∠BCR = y PAB is a line ∠PAR + ∠BAC = 180° x + 90° = 180° x = 180° − 90° x = 90° QBC is a line ∠ABQ + ∠ABC = 180° z + 30° = 180° z = 180° − 30° z = 150° In ∆ ABC Sum of the angles = 180° ∠BAC+ ∠ABC + ∠ACB = 180° 90° + 30° + ∠1 = 180° 120° + ∠1 = 180° ∠ 1 = 180° − 120° ∠ 1 = 60° Now, AR is a line ∠BCR + ∠ACB = 180° y + 60° = 180° y = 180° − 60° y = 120° Thus, x = 90° , y = 120° , z = 150° Hence, x + y + z = 90° + 120° + 150° = 360°