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Ex 5.3, 6 (i) - Chapter 5 Class 8 Squares and Square Roots
Last updated at August 10, 2026 by Teachoo
Smallest number divided to get perfect square
Chapter 5 Class 8 Squares and Square Roots
Concept wise
- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
- Pattern Solving
- Finding square of large numbers
- Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
-
Smallest number divided to get perfect square
- Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions
Transcript
Ex 5.3, 6 For each of the following numbers, find the smallest whole number by which it should be divided so as to get a perfect square. Also find the square root of the square number so obtained. (i) 252Prime factorizing 252 We see that , 252 = 2 × 2 × 3 × 3 × 7 Since 7 does not occur in pairs, we divide by 7 to make it a pair So, our number becomes 252 × 𝟏/𝟕 = 2 × 2 × 3 × 3 × 7 × 𝟏/𝟕 36 = 2 × 2 × 3 × 3 Square root of 36 :- ∴ √36 = 2 × 3 = 6 ∴ The smallest whole number to be divided = 7 and square root of new number = 6
