Let’s do this by example

Square root of 529 by long division

36.jpg

 

Therefore,

Square root of 529 = 23

 

Individual Steps are explained

 

Step 1:

  • Write the number
  • We make pairs from right.

So, 29 is a pair, but 5 is not in pair.

37.jpg

 

Step 2:

Now we find that number whose

square is less than or equal to 5.

1 × 1 = 1

2 × 2 = 4

3 × 3 = 9

Since 9 > 5, we use 2 × 2.

38.jpg

 

So writing 2 on left side & top.

& 4 below 5

Now we find remainder,

5 − 4 = 1

39.jpg

 

Step 3

Pair 29 comes down.

40.jpg

 

Step 4

We multiply the number above by 2

& add a blank after it

So, we write 2 × 2 = 4

4 _

41.jpg

 

Step 5

Find a number which is less than

Or equal to 129

41 × 1 = 41

42 × 2 = 84

43 × 3 = 129

 

Since 43 × 3 = 129. We use that

 

Thus,

Square root of 529 = 23

42.jpg

 

Square root of 4096 by long division

43.jpg

Therefore,

Square root of 4096 is 64

 

Individual Steps are explained

 

Step 1:

  • Write the number
  • We make pairs from right.

So, 96 and 40 are two pairs.

44.jpg

 

Step 2:

Now, we find that number whose

square is less than or equal to 40.

5 × 5 = 25

6 × 6 = 36

7 × 7 = 49

Since 49 > 40, we use 6 × 6 = 36

45.jpg

 

So writing 6 on top and left side

& 36 below 40

Now we find remainder,

40 − 36 = 4

46.jpg

 

Step 3

Pair 96 comes down.

47.jpg

 

Step 4

We multiply the number above

by 2 & add a blank after it

So, we write 6 × 2 = 12

12 _

48.jpg

 

Step 5

Find a number which is less than

Or equal to 496

124 × 1 = 124

124 × 2 = 248

124 × 3 = 372

124 × 4 = 496

 

Since 124 × 4 = 496. We use that

 

Thus, square root of 4096 = 64

49.jpg

 

  1. Chapter 6 Class 8 Squares and Square Roots
  2. Concept wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.