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Example 10 - Chapter 6 Class 8 Squares and Square Roots
Last updated at Sept. 11, 2018 by Teachoo
Transcript
Example 10 Find the least number that must be subtracted from 5607 so as to get a perfect square. Also find the square root of the perfect square. Finding square root of 5607 by long division Here, Remainder = 131 Since remainder is not 0, So, 5607 is not a perfect square Rough 143 × 3 = 429 144 × 4 = 576 144 × 4 = 725 We need to find the least number that must be subtracted from 5607 so as to get a perfect square Thus, we subtract 131 (remainder) from 5607 to get a perfect square. ∴ Perfect square = 5607 − 131 Perfect square = 5476 Also, If we do long division with 5476 We get 74 as square root ∴ Square root of 5476 = 74
Least number subtracted to get a perfect square
Chapter 6 Class 8 Squares and Square Roots
Concept wise
- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
- Pattern Solving
- Finding square of large numbers
- Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
- Smallest number divided to get perfect square
- Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.