# Example 10 - Chapter 6 Class 8 Squares and Square Roots

Last updated at Sept. 11, 2018 by Teachoo

Last updated at Sept. 11, 2018 by Teachoo

Transcript

Example 10 Find the least number that must be subtracted from 5607 so as to get a perfect square. Also find the square root of the perfect square. Finding square root of 5607 by long division Here, Remainder = 131 Since remainder is not 0, So, 5607 is not a perfect square Rough 143 × 3 = 429 144 × 4 = 576 144 × 4 = 725 We need to find the least number that must be subtracted from 5607 so as to get a perfect square Thus, we subtract 131 (remainder) from 5607 to get a perfect square. ∴ Perfect square = 5607 − 131 Perfect square = 5476 Also, If we do long division with 5476 We get 74 as square root ∴ Square root of 5476 = 74

Least number subtracted to get a perfect square

Chapter 6 Class 8 Squares and Square Roots

Concept wise

- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
- Pattern Solving
- Finding square of large numbers
- Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
- Smallest number divided to get perfect square
- Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.