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Ex 5.1, 6 Using the given pattern, find the missing numbers. 1^2 + 2^2+2^2 = 3^2 1^2 + 3^2+6^2 = 7^2 3^2 + 4^2+12^2 = 13^2 4^2 + 5^2+〖__〗^2 = 21^2 5^2 + 〖__〗^2+30^2 = 31^2 6^2 + 7^2+__ = 〖__〗^2Third number = 1st Number × 2nd Number Fourth number = 3rd Number + 1 𝟒^𝟐 + 𝟓^𝟐+〖__〗^𝟐 = 〖𝟐𝟏〗^𝟐 Now, 3rd number = 4 × 5 = 20 ∴ 4^2 + 5^2+〖𝟐𝟎〗^𝟐 = 21^2 𝟓^𝟐 + 〖__〗^𝟐+〖𝟑𝟎〗^𝟐 = 〖𝟑𝟏〗^𝟐 Now, 3rd number = 1st number × 2nd number 3rd number = 5 × 2nd number 30 = 5 × 2nd number 30/5 = 2nd number 6 = 2nd number 2nd number = 6 ∴ 𝟓^𝟐 + 𝟔^𝟐+〖𝟑𝟎〗^𝟐 = 〖𝟑𝟏〗^𝟐 ∴ 5^2 + 𝟔^𝟐+30^2 = 31^2 𝟔^𝟐 + 𝟕^𝟐+__ = 〖__〗^𝟐 Now, 3rd number = 1st number × 2nd number 3rd number = 6 × 7 = 42 Also, 4th number = 3rd number + 1 = 42 + 1 = 43 ∴ 6^2 + 7^2+〖𝟒𝟐〗^𝟐 = 〖𝟒𝟑〗^𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo