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Ex 5.1, 6 - Chapter 5 Class 8 Squares and Square Roots
Last updated at Dec. 16, 2024 by Teachoo
Chapter 5 Class 8 Squares and Square Roots
Concept wise
- Square numbers
- Properties of square numbers
- Sum of consecutive odd numbers
- Numbers between square numbers
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Pattern Solving
- Finding square of large numbers
- Pythagorean triplets
- Square root
- Finding Square root through repeated subtraction
- Finding Square root through prime factorisation
- Checking if perfect square by prime factorisation
- Smallest number multiplied to get perfect square
- Smallest number divided to get perfect square
- Smallest square number divisible by numbers
- Finding number of digits in square root (without calculation)
- Finding square root by division method - Integers
- Least number subtracted to get a perfect square
- Least number added to get a perfect square
- Finding square root by division method - Decimals
- Statement Questions
Transcript
Ex 5.1, 6 Using the given pattern, find the missing numbers. 1^2 + 2^2+2^2 = 3^2 1^2 + 3^2+6^2 = 7^2 3^2 + 4^2+12^2 = 13^2 4^2 + 5^2+〖__〗^2 = 21^2 5^2 + 〖__〗^2+30^2 = 31^2 6^2 + 7^2+__ = 〖__〗^2Third number = 1st Number × 2nd Number Fourth number = 3rd Number + 1 𝟒^𝟐 + 𝟓^𝟐+〖__〗^𝟐 = 〖𝟐𝟏〗^𝟐 Now, 3rd number = 4 × 5 = 20 ∴ 4^2 + 5^2+〖𝟐𝟎〗^𝟐 = 21^2 𝟓^𝟐 + 〖__〗^𝟐+〖𝟑𝟎〗^𝟐 = 〖𝟑𝟏〗^𝟐 Now, 3rd number = 1st number × 2nd number 3rd number = 5 × 2nd number 30 = 5 × 2nd number 30/5 = 2nd number 6 = 2nd number 2nd number = 6 ∴ 𝟓^𝟐 + 𝟔^𝟐+〖𝟑𝟎〗^𝟐 = 〖𝟑𝟏〗^𝟐 ∴ 5^2 + 𝟔^𝟐+30^2 = 31^2 𝟔^𝟐 + 𝟕^𝟐+__ = 〖__〗^𝟐 Now, 3rd number = 1st number × 2nd number 3rd number = 6 × 7 = 42 Also, 4th number = 3rd number + 1 = 42 + 1 = 43 ∴ 6^2 + 7^2+〖𝟒𝟐〗^𝟐 = 〖𝟒𝟑〗^𝟐
