Ex 3.1, 5 - Chapter 3 Class 7 Data Handling

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Ex 3.1, 5 - Following table shows the points of each player scored in

Ex 3.1, 5 - Chapter 3 Class 7 Data Handling - Part 2
Ex 3.1, 5 - Chapter 3 Class 7 Data Handling - Part 3
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Ex 3.1, 5 - Chapter 3 Class 7 Data Handling - Part 5 Ex 3.1, 5 - Chapter 3 Class 7 Data Handling - Part 6

Transcript

Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (i) Find the mean to determine A’s average number of points scored per game. Average points of A = (π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘œπ‘–π‘›π‘‘π‘  π‘œπ‘“ 𝐴 𝑖𝑛 π‘Žπ‘™π‘™ π‘”π‘Žπ‘šπ‘’π‘ )/(π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘Žπ‘šπ‘’π‘  𝐴 π‘π‘™π‘Žπ‘¦π‘’π‘‘) = (14 + 16 + 10 + 10)/4 = 50/4 = 25/2 = 12.5 Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (ii) To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why? Mean points of C = (π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘œπ‘–π‘›π‘‘π‘  π‘œπ‘“ 𝐢 𝑖𝑛 π‘Žπ‘™π‘™ π‘”π‘Žπ‘šπ‘’π‘ )/(π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘Žπ‘šπ‘’π‘  𝐢 π‘π‘™π‘Žπ‘¦π‘’π‘‘) Number of games C played = 3 So, we divide the total by 3 Let’s also find the mean of C Mean points of C = (π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘œπ‘–π‘›π‘‘π‘  π‘œπ‘“ 𝐢 𝑖𝑛 π‘Žπ‘™π‘™ π‘”π‘Žπ‘šπ‘’π‘ )/(π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘Žπ‘šπ‘’π‘  𝐢 π‘π‘™π‘Žπ‘¦π‘’π‘‘) = (8 + 11 + 13)/3 = 32/3 = 10.66.. Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (iii) B played in all the four games. How would you find the mean?Mean = (π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘œπ‘–π‘›π‘‘π‘  π‘œπ‘“ 𝐡)/(π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘Žπ‘šπ‘’π‘  𝐡 π‘π‘™π‘Žπ‘¦π‘’π‘‘) = (0 + 8 + 6 + 4)/4 = 18/4 = 4.5 Ex 3.1, 5 Following table shows the points of each player scored in four games: Now answer the following questions: (iv) Who is the best performer? Mean of A = 12.5 Mean of B = 4.5 Mean of C = 10.66 Since mean of A is highest, A is the best performer

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.