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  1. Chapter 5 Class 6 Understanding Elementary Shapes
  2. Serial order wise
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Transcript

Ex 5.2, 7 Where will the hour hand of a clock stop if it starts (a) from 6 and turns through 1 right angle? If it starts from 6 & turns 1 right angle, It will end up at 9 We know that 1 right angle = 1/4 of revolution = 1/4 × 12 hours = 3 hours Ex 5.2, 7 Where will the hour hand of a clock stop if it starts (b) from 8 and turns through 2 right angles? We know that 1 right angle = 1/4 of revolution = 1/4 × 12 hours = 3 hours We start from 8, Move 1 right angle (3 hours) to 11 And then we move Another right angle (3 hours) to 2 Ex 5.2, 7 Where will the hour hand of a clock stop if it start (c) from 10 and turns through 3 right angles? We know that 1 right angle = 1/4 of revolution = 1/4 × 12 hours = 3 hours We start from 10, & turn 1 right angle to 1 (3 hours) Then, we move another right angle to 4 (3 hours) Then, we move another right angle to 7 (3 hours) Ex 5.2, 7 Where will the hour hand of a clock stop if it starts (d) from 7 and turns through 2 straight angles? We know that 1 straight angle = 1/2 of revolution = 1/2 × 12 hours = 6 hours We start from 7, and move 1 straight angle (12 hours) to 1 We start from 7, and move 1 straight angle (12 hours) to 1

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.