Ex 1.3, 7 - Chapter 1 Class 7 Integers

Last updated at July 14, 2026 by

Ex 1.3, 7 - An elevator descends into a mine shaft at rate of 6 m/min - Ex 1.3

part 2 - Ex 1.3, 7 - Ex 1.3 - Serial order wise - Chapter 1 Class 7 Integers

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Ex 1.3, 7 An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.Now, Total distance elevator has to travel = Initial position − Final position = 10 − (−350) = 10 + 350 = 360 m Now, Elevator descends at rate 6m / min Elevator travels 6 m in = 1 minute Elevator travels 1 m in = 𝟏/𝟔 minute Elevator travels 360 m in = 𝟏/𝟔 × 360 minutes = 60 minutes = 1 hour ∴ It will take the elevator 1 hour to reach −350 m

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