3.7 - 1.jpg

Ex 3.7, 9 - Chapter 3 Class 6 Playing with Numbers - Part 2
Ex 3.7, 9 - Chapter 3 Class 6 Playing with Numbers - Part 3

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Transcript

Let’s first find smallest number divisible by 18, 24, 32 Smallest number divisible by 18, 24, 32 = LCM of 18, 24, 32 LCM of 18, 24, 32 LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288 ∴ 288 is the smallest number divisible by 18, 24, 32 Now, We need to find smallest 4-digit number divisible by 18, 24, 32 Smallest 4 digit number = 1000 we divide 1000 by 288 So remainder is 136 But we need to find a number where remainder is 0. Required number = 1000 + (288 − 136) = 1000 + 152 = 1152 So, 1152 is the smallest 4 digit number

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo