Ex 3.7, 8 - Find least number which when divided by 6, 15 and 18

Ex 3.7, 8 - Chapter 3 Class 6 Playing with Numbers - Part 2


Transcript

Least number when divided by 6, 15, 18 and leaves remainder 0 = LCM of 6, 15, 18 So, LCM leaves remainder 0 In the question, We are asked least number which leaves remainder 5 So, Required number will be 5 more than LCM ∴ Required number = LCM + 5 ∴ LCM = 2 × 3 × 3 × 5 = 90 So, Required number = LCM + 5 = 90 + 5 = 95

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.