Ex 3.7, 5 - Chapter 3 Class 6 Playing with Numbers

Last updated at Dec. 16, 2024 by

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Ex 3.7, 5 - Chapter 3 Class 6 Playing with Numbers - Part 2
Ex 3.7, 5 - Chapter 3 Class 6 Playing with Numbers - Part 3

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Lets find smallest number divisible by 8, 10, 12 Smallest number divisible by 8, 10, 12 = LCM of 8, 10, 12 LCM of 8, 10, 12 So LCM = 2 × 2 × 2 × 3 × 5 = 120 ∴ 120 is the smallest number divisible by 8, 10, 12 Now, We need to find greatest 3-digit number divisible by 8, 10 and 12 Greatest 3 digit number = 999 We divide 999 by 120 So remainder is 39 But we need to find a number where remainder is 0. ∴ Required number = 999 − 39 = 960 So, 960 is the greatest 3 digit number

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo