Ex 13.2, 6 - Chapter 15 Class 11 Statistics (Important Question)

Last updated at December 16, 2024 by

Ex 13.2, 6 - Find mean, standard deviation using short-cut - Ex 13.2

part 2 - Ex 13.2, 6 - Ex 13.2 - Serial order wise - Chapter 13 Class 11 Statistics

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Ex 13.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (āˆ‘ā–’š‘“š‘–š‘¦š‘–)/(āˆ‘ā–’š‘“š‘–) Ɨ h = 64 + 0/100 Ɨ1 = 64 Standard Deviation = ā„Ž/š‘ āˆš(š‘āˆ‘ā–’š‘“š‘–š‘¦š‘–2 āˆ’ (āˆ‘ā–’š‘“š‘–š‘¦š‘–)^2 ) "= " 1/100 āˆš("100" Ɨ"286 ā€“ " 怖(0)怗^2 ) = 1/100 āˆš28600 = 169.1/100 = 1.691

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