Ex 13.2, 6 - Chapter 15 Class 11 Statistics (Important Question)
Last updated at May 7, 2024 by Teachoo
Chapter 15 Class 11 Statistics
Chapter 15 Class 11 Statistics
Last updated at May 7, 2024 by Teachoo
Ex 13.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (∑▒𝑓𝑖𝑦𝑖)/(∑▒𝑓𝑖) × h = 64 + 0/100 ×1 = 64 Standard Deviation = ℎ/𝑁 √(𝑁∑▒𝑓𝑖𝑦𝑖2 − (∑▒𝑓𝑖𝑦𝑖)^2 ) "= " 1/100 √("100" ×"286 – " 〖(0)〗^2 ) = 1/100 √28600 = 169.1/100 = 1.691