Formation of Differntial equation when general solution given
Formation of Differntial equation when general solution given
Last updated at August 5, 2026 by Teachoo
Transcript
Question 3 Form a differential equation representing the given family of curves by eliminating arbitrary constants š and š. š¦=š š^3š„+š š^(ā2š„) Since it has two variables, we will differentiate twice š¦=š š^3š„+š š^(ā2š„) ā“ Differentiating Both Sides w.r.t. š„ šš¦/šš„=š/šš„ [šš^3š„+š š^(ā2š„) ] =šš^3š„Ć3+š š^(ā2š„)Ć(ā2) =3šš^3š„ā2š š^(ā2š„) ā“ š¦^ā²=3šš^3š„ā2š š^(ā2š„) ...(1) š¦^ā²=3šš^3š„ā2š š^(ā2š„) Again differentiating w.r.t. š„ š¦^ā²ā²=š/šš„ [3šš^3š„ā2š š^(ā2š„) ] š¦^ā²ā²=3šš^3š„ (3)ā2š š^(ā2š„) (ā2) ā“ š¦^ā²ā²=9šš^3š„+4š š^(ā2š„) Subtracting (2) From (1) š¦^ā²ā²āš¦^ā²=9šš^3š„+4š š^(ā2š„)ā3šš^3š„+2š š^(ā2š„) š¦^ā²ā²āš¦^ā²=6šš^3š„+6š š^(ā2š„) š¦^ā²ā²āš¦^ā²=6(šš^3š„+šš^(ā2š„)) š¦^ā²ā²āš¦^ā²=6y š^ā²ā²āš^ā²āšš=š is the required differential equation. (As y = š^3š„ + bš^3š„)