Ex 9.5, 4 - Find general solution: dy/dx + (sec x) y = tan x - Ex 9.5

part 2 - Ex 9.5, 4 - Ex 9.5 - Serial order wise - Chapter 9 Class 12 Differential Equations

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Ex 9.5, 4 For each of the differential equation given in Exercises 1 to 12, find the general solution : 𝑑𝑦/𝑑π‘₯+(sec⁑π‘₯ )𝑦=π‘‘π‘Žπ‘›π‘₯(0≀π‘₯<πœ‹/2) Differential equation is of the form 𝑑𝑦/𝑑π‘₯ + Py = Q where P = sec x and Q = tan x Finding integrating factor, IF = 𝑒^∫1▒〖𝑝 𝑑π‘₯γ€— IF = e^∫1β–’sec⁑〖π‘₯ 𝑑π‘₯γ€— IF = γ€–e^π‘™π‘œπ‘”γ€—^|sec⁑〖π‘₯ + tan⁑π‘₯ γ€— | I.F = sec x + tan x Solution is y (IF) = ∫1β–’(𝑄×𝐼.𝐹) 𝑑π‘₯+𝑐 y (sec x + tan x) = ∫1β–’γ€–π­πšπ§β‘π’™ (𝒔𝒆𝒄⁑𝒙+π­πšπ§β‘γ€–π’™)γ€— γ€—+𝒄 y (sec x + tan x) = ∫1β–’γ€–tan⁑π‘₯ sec⁑π‘₯ γ€— 𝑑π‘₯+∫1β–’γ€–tan^2⁑π‘₯ 𝑑π‘₯+𝐢〗 y (sec x + tan x) = sec x + ∫1β–’γ€–(sec^2⁑π‘₯βˆ’1)γ€— dx + c y (sec x + tan x) = sec x + π­πšπ§β‘π’™ βˆ’ x + c

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