Ex 6.2, 8 Solve the given inequality graphically in two-dimensional plane: 3y – 5x < 30 3y – 5x < 30 Lets first draw graph of 3y – 5x = 30 Putting x = 0 in (1) 3y – 5(0) = 30 3y – 0 = 30 3y = 30 y = 30/3 y = 10 Putting y = 0 in (1) 3(0) – 5x = 30 0 – 5x = 30 –5x = 30 x = −6 Points to be plotted are (0, 10) , (−6, 0) Drawing graph Checking for (0,0) Putting x = 0, y = 0 3y – 5x < 30 3(0) – 5(0) < 30 0 < 30 which is true Hence origin lies in plane. So, we shade right side of line

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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