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  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise

Transcript

Ex 6.2, 4 Solve the given inequality graphically in two-dimensional plane: y + 8 ≥ 2x y + 8 ≥ 2x Lets first draw graph of y + 8 = 2x VPutting y = 0 in (1) 0 + 8 = 2x 8 = 2x 2x = 8 x = 8/2 x = 4 Drawing graph Checking for (0,0) Putting x = 0, y = 0 y + 8 ≥ 2x 0 + 8 ≥ 2(0) 8 ≥ 0 which is true Hence origin lies in the plane y + 8 ≥ 2x So, we shade left side of line Points to be plotted are (4, 0) , (0, – 8)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.