Subscribe to our Youtube Channel - https://www.youtube.com/channel/UCZBx269Tl5Os5NHlSbVX4Kg

Slide5.JPG

Slide6.JPG

  1. Chapter 6 Class 11 Linear Inequalities
  2. Serial order wise

Transcript

Ex 6.2, 3 Solve the given inequality graphically in two-dimensional plane: 3x + 4y ≤ 12 3x + 4y ≤ 12 Lets first draw graph of 3x + 4y = 12 Putting x = 0 in (1) 3(0) + 4y = 12 0 + 4y = 12 4y = 12 y = 12/4 y = 3 Putting y = 0 in (1) 3x + 4(0) = 12 3x + 0 = 12 3x = 12 x = 12/3 x = 4 Drawing graph Checking for (0,0) Putting x = 0, y = 0 3x + 4y ≤ 12 3(0) + 2(0) ≤ 12 0 ≤ 12 which is true Hence origin lies in plane So, we shade left side of line Points to be plotted are (0, 3), (4, 0)

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.