Theorem 8.6 - Chapter 8 Class 9 Quadrilaterals

Last updated at August 5, 2026 by

Theorem 8.6 - Class 9 - Diagonals of a parallelogram bisect each other - Theorems

part 2 - Theorem 8.6 - Theorems - Serial order wise - Chapter 8 Class 9 Quadrilaterals

 

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Theorem 8.6 The diagonals of a parallelogram bisect each other Given : ABCD is a Parallelogram with AC and BD diagonals & O is the point of intersection of AC and BD To Prove : OA = OC & OB = OD Proof : Since, opposite sides of Parallelogram are parallel. In AOD and BOC OAD = OCB AD = CB ODA = OBC AOD BOC So, OA = OC & OB = OD Hence Proved

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