Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Last updated at May 29, 2023 by Teachoo
Ex 4.2, 3 Check which of the following are solutions of the equation π₯β2π¦=4 and which are not: (i) (0, 2) Given equation π₯β2π¦=4 Putting x = 0 and y = 2 in LHS πβππ =0β2(2) =βπ β 4 Since, LHS β RHS Hence, (0, 2) is not a solution