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Example 8 (Method 1) Find the remainder obtained on dividing 𝑝(π‘₯)=π‘₯^3+1 by π‘₯+1 Dividing 𝒙^πŸ‘+𝟏 by 𝒙+𝟏 Step 1: Putting Divisor = 0 x + 1 = 0 x = βˆ’1 Step 2: Let 𝑝(π‘₯)=π‘₯^3+1 Putting x = βˆ’1 𝑝(βˆ’πŸ)=γ€–(βˆ’πŸ)γ€—^3+1 =βˆ’1+1 =0 Thus, Remainder =𝒑(βˆ’πŸ)=𝟎 Example 8 (Method 2) Find the remainder obtained on dividing 𝑝(π‘₯)=π‘₯^3+1 by π‘₯+1 By long division Hence, the remainder is 0

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.