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Example 8 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at Jan. 31, 2022 by Teachoo
Chapter 2 Class 9 Polynomials
Concept wise
- Definition
- Degree & Coefficient of a polynomial
- Value of a polynomial at a given point
- Verifying Zeroes of a polynomial
- Finding Zeroes of a polynomial
-
Remainder Theoram
- Check if factor
- Factorisation by middle term
- Factorisation by factor formula
- Factorizing cubic equation
- Identity I - IV
- Identity V
- Identity VI & VII
- Identity VIII
Transcript
Example 8 (Method 1) Find the remainder obtained on dividing π(π₯)=π₯^3+1 by π₯+1 Dividing π^π+π by π+π Step 1: Putting Divisor = 0 x + 1 = 0 x = β1 Step 2: Let π(π₯)=π₯^3+1 Putting x = β1 π(βπ)=γ(βπ)γ^3+1 =β1+1 =0 Thus, Remainder =π(βπ)=π Example 8 (Method 2) Find the remainder obtained on dividing π(π₯)=π₯^3+1 by π₯+1 By long division Hence, the remainder is 0
