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Ex 8.2, 7 - Area lying between y2 = 4x and y = 2x is - Area between curve and line

Ex 8.2 , 7 - Chapter 8 Class 12 Application of Integrals - Part 2
Ex 8.2 , 7 - Chapter 8 Class 12 Application of Integrals - Part 3
Ex 8.2 , 7 - Chapter 8 Class 12 Application of Integrals - Part 4
Ex 8.2 , 7 - Chapter 8 Class 12 Application of Integrals - Part 5

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Ex 8.2 , 7 Area lying between the curves 2 = 4 and =2 is (A) (B) (C) (D) Step 1: Drawing figure Parabola is 2 =4x Also, =2 passes through (0, 0) & (1, 2) Point (1, 2) lies in parabola y2 = 4x Hence, intersecting point A = (1, 2) Area required Area required = Area OBAD Area OAD Area OBAD Area OBAD = 0 1 y Equation of parabola 2 = 4x = 4x = 2 x Therefore, Area OBAD = 0 1 2 x = 2 0 1 1 2 = 2 1 2 +1 1 2 +1 0 1 = 2 3 2 3 2 0 1 = 2 2 3 3 2 0 1 = 4 3 1 3 2 0 3 2 = 4 3 Area OAD Area OAD = 0 1 y Equation of line y = 2x Therefore, Area OAD = 0 1 2 = 2 0 1 = 2 2 2 0 1 = 2 1 2 2 0 1 = 1 2 0 2 = 1 Area required = Area OBAD Area OAD = 4 3 1 = 1 3 So, B is correct option

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.