Questions at the end of the chapter
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Questions at the end of the chapter
Last updated at June 30, 2026 by Teachoo
A motorbike moving with initial velocity 28 m s⁻¹ and constant acceleration stops after travelling 98 m. Find the acceleration of the motorbike and the time taken to come to a stop.
\(u = 28\ \text{m s}^{-1},\ v = 0,\ s = 98\ \text{m}\).
Using \(v^2 = u^2 + 2as\): \(0 = 28^2 + 2a(98) \Rightarrow a = \dfrac{-784}{196} = -4\ \text{m s}^{-2}\).
Using \(v = u + at\): \(0 = 28 + (-4)t \Rightarrow t = 7\ \text{s}\).
